3. if 65.5 ml of hcl stock solution is used to make 450.-ml of a 0.675 m hcl dilution, what is the molarity…

3. if 65.5 ml of hcl stock solution is used to make 450.-ml of a 0.675 m hcl dilution, what is the molarity of the stock solution?

3. if 65.5 ml of hcl stock solution is used to make 450.-ml of a 0.675 m hcl dilution, what is the molarity of the stock solution?

Answer

Explanation:

Step1: Aplicar la ley de dilución

$M_1V_1 = M_2V_2$ Donde $M_1$ es la molaridad de la solución stock, $V_1$ es el volumen de la solución stock, $M_2$ es la molaridad de la solución diluida y $V_2$ es el volumen de la solución diluida.

Step2: Despejar $M_1$

$M_1=\frac{M_2V_2}{V_1}$ Sustituir los valores: $M_2 = 0.675\ M$, $V_2=450\ ml$ y $V_1 = 65.5\ ml$. $M_1=\frac{0.675\ M\times450\ ml}{65.5\ ml}$

Step3: Calcular $M_1$

$M_1=\frac{303.75}{65.5}\ M\approx4.64\ M$

Answer:

$4.64\ M$