92 grams of ethanol, c₂h₅oh, is dissolved in 1 liter of solution. determine the molarity (m).

Explanation:

Step1: Calculate molar mass of ethanol

The molar mass of $C_2H_5OH$: $C$ has an atomic mass of approximately 12 g/mol, $H$ has 1 g/mol and $O$ has 16 g/mol. $M_{C_2H_5OH}=2\times12 + 6\times1+16=46$ g/mol

Step2: Calculate number of moles of ethanol

Use the formula $n=\frac{m}{M}$, where $m = 92$ g and $M = 46$ g/mol. $n=\frac{92}{46}=2$ mol

Step3: Calculate molarity

Use the formula $M=\frac{n}{V}$, where $n$ is the number of moles and $V$ is the volume of the solution in liters. Here $n = 2$ mol and $V=1$ L. $M=\frac{2}{1}=2$ M

Answer:

2