which additional product balances the reaction h₂so₄ + 2naoh → na₂so₄ + ______?\no 2h₂o\no 2oh\no h₂o₂\no h₃o
which additional product balances the reaction h₂so₄ + 2naoh → na₂so₄ + ______?\no 2h₂o\no 2oh\no h₂o₂\no h₃o
Answer
Explanation:
Step1: Count atoms on reactant side
On the left - hand side of the reaction $\text{H}_2\text{SO}_4+2\text{NaOH}$, for hydrogen ($\text{H}$) atoms, we have $2$ from $\text{H}_2\text{SO}_4$ and $2$ from $2\text{NaOH}$, so a total of $4$ $\text{H}$ atoms. For oxygen ($\text{O}$) atoms, we have $4$ in $\text{H}_2\text{SO}_4$, $2$ in $2\text{NaOH}$, so a total of $6$ $\text{O}$ atoms. For sodium ($\text{Na}$) atoms, we have $2$ from $2\text{NaOH}$, and for sulfur ($\text{S}$) atoms, we have $1$ from $\text{H}_2\text{SO}_4$.
Step2: Analyze atoms on product side
On the right - hand side, in $\text{Na}_2\text{SO}_4$, we have $2$ $\text{Na}$ atoms, $1$ $\text{S}$ atom and $4$ $\text{O}$ atoms. We need to account for the remaining $4$ $\text{H}$ atoms and $2$ $\text{O}$ atoms.
Step3: Determine the product
The combination of $4$ $\text{H}$ atoms and $2$ $\text{O}$ atoms gives $2\text{H}_2\text{O}$ since each $\text{H}_2\text{O}$ molecule has $2$ $\text{H}$ atoms and $1$ $\text{O}$ atom.
Answer:
A. $2\text{H}_2\text{O}$