aluminum + oxygen yields aluminum oxide\nwrite a balanced equation for this chemical reaction.\na al + o →…
aluminum + oxygen yields aluminum oxide\nwrite a balanced equation for this chemical reaction.\na al + o → alo\nb al + o → al₂o₃\nc 2al + 3o₂ → al₂o₃\nd 4al + 3o₂ → 2al₂o₃
Answer
Explanation:
Step1: Identify reactants and products
Reactants are aluminum (Al) and oxygen ($O_2$), product is aluminum oxide ($Al_2O_3$).
Step2: Balance aluminum atoms
On the product side, there are 2 Al atoms in $Al_2O_3$. So, we need 2 Al atoms on the reactant side.
Step3: Balance oxygen atoms
There are 3 oxygen atoms in $Al_2O_3$. On the reactant side, oxygen is in the form of $O_2$. To get 6 oxygen atoms (common - multiple of 2 and 3), we need 3 $O_2$ molecules on the reactant side and 2 $Al_2O_3$ molecules on the product side. And to balance Al atoms with 2 $Al_2O_3$, we need 4 Al atoms on the reactant side. The balanced equation is $4Al + 3O_2\rightarrow2Al_2O_3$.
Answer:
D. $4Al + 3O_2\rightarrow2Al_2O_3$