ammonium hydrogen sulfide ($nh_{4}hs$) can decompose to ammonia and hydrogen sulfide:\n\n$nh_{4}hs(s)…

ammonium hydrogen sulfide ($nh_{4}hs$) can decompose to ammonia and hydrogen sulfide:\n\n$nh_{4}hs(s) \rightleftharpoons nh_{3}(g) + h_{2}s(g)$\n\nwhat is the equilibrium constant expression for this system?\n\n$k_{eq} = \\frac{nh_{3}h_{2}s}{nh_{4}hs}$\n\n$k_{eq} = nh_{3}h_{2}s$\n\n$k_{eq} = \\frac{1}{nh_{3}h_{2}s}$

ammonium hydrogen sulfide ($nh_{4}hs$) can decompose to ammonia and hydrogen sulfide:\n\n$nh_{4}hs(s) \rightleftharpoons nh_{3}(g) + h_{2}s(g)$\n\nwhat is the equilibrium constant expression for this system?\n\n$k_{eq} = \\frac{nh_{3}h_{2}s}{nh_{4}hs}$\n\n$k_{eq} = nh_{3}h_{2}s$\n\n$k_{eq} = \\frac{1}{nh_{3}h_{2}s}$

Answer

Answer:

$K_{eq} = [\text{NH}_3][\text{H}_2\text{S}]$