answer the following questions related to h2o.\nsubstance\tδg°f at 298 k (kj/mol)\nh2o (l)\t-237.2\nh2o…

answer the following questions related to h2o.\nsubstance\tδg°f at 298 k (kj/mol)\nh2o (l)\t-237.2\nh2o (g)\t-228.4\n(a) using the information in the table above, determine the value of δg° at 298 k for the process represented by the equation h2o (l) ⇌ h2o (g).

answer the following questions related to h2o.\nsubstance\tδg°f at 298 k (kj/mol)\nh2o (l)\t-237.2\nh2o (g)\t-228.4\n(a) using the information in the table above, determine the value of δg° at 298 k for the process represented by the equation h2o (l) ⇌ h2o (g).

Answer

Explanation:

Step1: Recall the formula for $\Delta G^{\circ}$ of a reaction

The formula for $\Delta G^{\circ}$ of a reaction $\Delta G^{\circ}=\sum n\Delta G_{f}^{\circ}(products)-\sum m\Delta G_{f}^{\circ}(reactants)$. For the reaction $\mathrm{H}{2}\mathrm{O}(l)\rightleftharpoons\mathrm{H}{2}\mathrm{O}(g)$, the number of moles of product $n = 1$ and reactant $m = 1$.

Step2: Substitute the values

$\Delta G^{\circ}=\Delta G_{f}^{\circ}(\mathrm{H}{2}\mathrm{O},g)-\Delta G{f}^{\circ}(\mathrm{H}{2}\mathrm{O},l)$. Substitute $\Delta G{f}^{\circ}(\mathrm{H}{2}\mathrm{O},g)= - 228.4\ \mathrm{kJ/mol}$ and $\Delta G{f}^{\circ}(\mathrm{H}_{2}\mathrm{O},l)=-237.2\ \mathrm{kJ/mol}$ into the formula. $\Delta G^{\circ}=-228.4-(-237.2)$ $\Delta G^{\circ}=-228.4 + 237.2$ $\Delta G^{\circ}=8.8\ \mathrm{kJ/mol}$

Answer:

$8.8\ \mathrm{kJ/mol}$