answer the questions about the following isotope $^{238}u^{+2}$. the atomic number, the number of protons…

answer the questions about the following isotope $^{238}u^{+2}$. the atomic number, the number of protons, is __1__. the mass number, the number of nucleons, is __2__. the number of neutrons is __3__. the number of electrons is __4__. the charge is __5__ making it an __6__. a. 0 b. 1 c. 2 d. 3 e. 4 f. -1 g. -2 h. -3 i. -4 j. 238 k. 92 l. 90 m. 146 n. element o. anion p. cation
Answer
Explanation:
Step1: Identify element uranium
Uranium (U) has an atomic number of 92, which is the number of protons. So for the number of protons, the answer is 92 (K).
Step2: Determine mass number
The isotope is written as (^{238}U^{+ 2}), and the mass - number is 238 (J).
Step3: Calculate number of neutrons
Neutrons = Mass number - Atomic number. So, (238−92 = 146) (M).
Step4: Calculate number of electrons
The atom is a (U^{+2}) ion. A neutral uranium atom has 92 electrons. Since it has a + 2 charge, it has lost 2 electrons. So, (92 - 2=90) (L).
Step5: Determine charge
The ion is (U^{+2}), so the charge is + 2 (C).
Step6: Classify the ion
A positively - charged ion is a cation (P).
Answer:
- K. 92
- J. 238
- M. 146
- L. 90
- C. 2
- P. cation