answer the questions below about the highlighted atom in this lewis structure: h h h - c - c - c≡n: in how…

answer the questions below about the highlighted atom in this lewis structure: h h h - c - c - c≡n: in how many sigma bonds does the highlighted atom participate? in how many pi bonds does the highlighted atom participate? what is the orbital hybridization of the highlighted atom?

answer the questions below about the highlighted atom in this lewis structure: h h h - c - c - c≡n: in how many sigma bonds does the highlighted atom participate? in how many pi bonds does the highlighted atom participate? what is the orbital hybridization of the highlighted atom?

Answer

Explanation:

Step1: Identify sigma - bonds

A single bond is a sigma bond. The highlighted carbon atom has 4 single bonds (3 C - H and 1 C - C). So it participates in 4 sigma bonds.

Step2: Identify pi - bonds

Pi - bonds are present in double and triple bonds. The highlighted carbon atom is only in single bonds, so it participates in 0 pi bonds.

Step3: Determine hybridization

The number of electron - group around the highlighted carbon atom is 4 (4 single bonds). When the number of electron - groups is 4, the hybridization is $sp^{3}$.

Answer:

In how many sigma bonds does the highlighted atom participate? 4 In how many pi bonds does the highlighted atom participate? 0 What is the orbital hybridization of the highlighted atom? $sp^{3}$