arrange the compounds below in decreasing order of the ionic character of the bonds in them. that is, pick 1…

arrange the compounds below in decreasing order of the ionic character of the bonds in them. that is, pick 1 for the compound with the most ionic bonds, pick 2 for the compound with the next most ionic bonds, and so on.

arrange the compounds below in decreasing order of the ionic character of the bonds in them. that is, pick 1 for the compound with the most ionic bonds, pick 2 for the compound with the next most ionic bonds, and so on.

Answer

Brief Explanations:

Ionic character is determined by the difference in electronegativity between the atoms in a compound. The greater the electronegativity difference, the more ionic the bond.

  • (Cl_2) is a non - polar covalent compound (electronegativity difference (= 0)), so it has the least ionic character ((4)).
  • (SCl_4) is a covalent compound. The electronegativity difference between (S) ((2.58)) and (Cl) ((3.16)) is relatively small.
  • For ionic compounds (LiCl) and (CsCl), we use the trend in electronegativity of metals. Electronegativity of (Li=0.98), (Cs = 0.79), and (Cl = 3.16). The electronegativity difference for (LiCl) is (|3.16 - 0.98|=2.18), and for (CsCl) is (|3.16 - 0.79| = 2.37). But due to the smaller size of (Li^+) compared to (Cs^+), according to Fajan's rules, (LiCl) has more covalent character than (CsCl). So (CsCl) ((2)) has more ionic character than (LiCl) ((3)).

Answer:

(Cl_2) ((4)) (<) (SCl_4) ((3)) (<) (LiCl) ((2)) (<) (CsCl) ((1))