atomic structure\nprotons\nneutrons\nelectrons\natomic calculation\natomic # = #p\n#p = #e\nmass # = #p +…

atomic structure\nprotons\nneutrons\nelectrons\natomic calculation\natomic # = #p\n#p = #e\nmass # = #p + #n\ndetermine the atomic number and identify the atom by using the periodic table.\nisotope\nsymbol - mass\nisotope notation\nmass#px\n#protons = 5\natomic # = \n#electrons = \n#neutrons = \nmass # = \n#protons = \natomic # = \n#electrons = \n#neutrons = \nmass # = \n14 6c

atomic structure\nprotons\nneutrons\nelectrons\natomic calculation\natomic # = #p\n#p = #e\nmass # = #p + #n\ndetermine the atomic number and identify the atom by using the periodic table.\nisotope\nsymbol - mass\nisotope notation\nmass#px\n#protons = 5\natomic # = \n#electrons = \n#neutrons = \nmass # = \n#protons = \natomic # = \n#electrons = \n#neutrons = \nmass # = \n14 6c

Answer

Explanation:

Step1: Recall atomic - structure relationships

The atomic number ((Z)) is equal to the number of protons ((#P)). In a neutral atom, the number of electrons ((#e)) is equal to the number of protons. The mass number ((A)) is the sum of the number of protons and neutrons ((#N)), i.e., (A=#P+#N).

Step2: First - row calculations

Given (#P = 5). The atomic number (Z=#P = 5). Since (#e=#P), (#e = 5). Counting the neutrons in the diagram, (#N=6). Then the mass number (A=#P+#N=5 + 6=11).

Step3: Second - row calculations

For the isotope (^{14}_6C), the sub - script is the atomic number (Z = 6), so (#P=Z = 6). Since (#e=#P), (#e = 6). The mass number (A = 14), and (#N=A-#P=14 - 6=8).

Answer:

First row: Atomic (#=5), (#)electrons ( = 5), (#)neutrons (=6), Mass (# = 11) Second row: (#)Protons (=6), Atomic (#=6), (#)electrons ( = 6), (#)neutrons (=8), Mass (# = 14)