balance the chemical equation below using the smallest possible whole number stoichiometric…

balance the chemical equation below using the smallest possible whole number stoichiometric coefficients.\nbr₂(l) + i₂(s) → ibr₃(g)

balance the chemical equation below using the smallest possible whole number stoichiometric coefficients.\nbr₂(l) + i₂(s) → ibr₃(g)

Answer

Explanation:

Step1: Balance Br atoms

On the left - hand side, we have (Br_2) (2 Br atoms). On the right - hand side, we have (IBr_3) (3 Br atoms). The least common multiple of 2 and 3 is 6. So, we put a coefficient of 3 in front of (Br_2) and 2 in front of (IBr_3). The equation becomes (3Br_2(l)+I_2(s)\to2IBr_3(g))

Step2: Balance I atoms

On the left - hand side, we have (I_2) (2 I atoms). On the right - hand side, we have (2IBr_3) (2 I atoms). The I atoms are already balanced.

Answer:

(3Br_2(l)+I_2(s) = 2IBr_3(g))