balance the chemical equation below using the smallest possible whole number stoichiometric coefficients…

balance the chemical equation below using the smallest possible whole number stoichiometric coefficients. ch3(ch2)3ch3(l) + o2(g) → co2(g) + h2o(g)

balance the chemical equation below using the smallest possible whole number stoichiometric coefficients. ch3(ch2)3ch3(l) + o2(g) → co2(g) + h2o(g)

Answer

Explanation:

Step1: Count atoms on each side

Left - side: C - 5, H - 12, O - 2; Right - side: C - 1, H - 2, O - 3.

Step2: Balance carbon atoms

Put 5 in front of $CO_2$ to balance C. The equation becomes $C_5H_{12}(l)+O_2(g)\rightarrow5CO_2(g)+H_2O(g)$.

Step3: Balance hydrogen atoms

Put 6 in front of $H_2O$ to balance H. The equation is $C_5H_{12}(l)+O_2(g)\rightarrow5CO_2(g)+6H_2O(g)$.

Step4: Balance oxygen atoms

Calculate the total O atoms on the right - side: $5\times2 + 6\times1=16$. So put 8 in front of $O_2$ on the left - side. The balanced equation is $C_5H_{12}(l)+8O_2(g)\rightarrow5CO_2(g)+6H_2O(g)$.

Answer:

$C_5H_{12}(l)+8O_2(g)\rightarrow5CO_2(g)+6H_2O(g)$