balance the chemical equation using the smallest possible whole - number coefficients. if the coefficient is…

balance the chemical equation using the smallest possible whole - number coefficients. if the coefficient is 1, you may leave it blank. \n squaremathrm{al}_{(s)}+squaremathrm{cl}_{2(g)}longrightarrowsquaremathrm{alcl}_{3(s)}

balance the chemical equation using the smallest possible whole - number coefficients. if the coefficient is 1, you may leave it blank. \n squaremathrm{al}_{(s)}+squaremathrm{cl}_{2(g)}longrightarrowsquaremathrm{alcl}_{3(s)}

Answer

Explanation:

Step1: Balance chlorine atoms

There are 2 chlorine atoms in $Cl_2$ and 3 chlorine atoms in $AlCl_3$. The least - common multiple of 2 and 3 is 6. So, we put a 3 in front of $Cl_2$ and a 2 in front of $AlCl_3$. $Al(s)+3Cl_2(g)\rightarrow2AlCl_3(s)$

Step2: Balance aluminum atoms

Now, there are 2 aluminum atoms on the right - hand side. So, we put a 2 in front of $Al$ on the left - hand side. $2Al(s)+3Cl_2(g)\rightarrow2AlCl_3(s)$

Answer:

2, 3, 2