balance the following equations by inserting the proper coefficients.\nch₄ + (square)o₂ → co₂ +…

Explanation:

Step1: Balance the first equation

For $CH_4 + \square O_2\rightarrow CO_2+\square H_2O$, balance hydrogen first. There are 4 hydrogen atoms in $CH_4$, so we need 2 moles of $H_2O$. Then balance oxygen. There are 4 oxygen atoms in $CO_2$ and 2 oxygen atoms in 2 moles of $H_2O$, so we need 2 moles of $O_2$. The balanced equation is $CH_4 + 2O_2\rightarrow CO_2+2H_2O$.

Step2: Balance the second equation

For $CaCl_2+\square AgNO_3\rightarrow Ca(NO_3)_2+\square AgCl$, balance chlorine first. There are 2 chlorine atoms in $CaCl_2$, so we need 2 moles of $AgCl$. Then balance silver and nitrate. We need 2 moles of $AgNO_3$. The balanced equation is $CaCl_2 + 2AgNO_3\rightarrow Ca(NO_3)_2+2AgCl$.

Step3: Balance the third equation

For $C_2H_6O+\square O_2\rightarrow\square CO_2+\square H_2O$, balance carbon first. There are 2 carbon atoms in $C_2H_6O$, so we need 2 moles of $CO_2$. Then balance hydrogen. There are 6 hydrogen atoms in $C_2H_6O$, so we need 3 moles of $H_2O$. Then balance oxygen. There are 2 oxygen atoms in $C_2H_6O$, and in 2 moles of $CO_2$ there are 4 oxygen - atoms and in 3 moles of $H_2O$ there are 3 oxygen atoms. So we need 3 moles of $O_2$. The balanced equation is $C_2H_6O + 3O_2\rightarrow 2CO_2+3H_2O$.

Answer:

1. $CH_4 + 2O_2\rightarrow CO_2+2H_2O$
2. $CaCl_2 + 2AgNO_3\rightarrow Ca(NO_3)_2+2AgCl$
3. $C_2H_6O + 3O_2\rightarrow 2CO_2+3H_2O$