balance this reaction.\nch₃oh + o₂ → co₂ + h₂o\n3\nblank\n4\n2

Explanation:

Step1: Balance carbon atoms

There is 1 carbon atom in $CH_3OH$. So, the coefficient of $CO_2$ should be 1 to balance carbon. $CH_3OH + O_2\rightarrow1CO_2 + H_2O$

Step2: Balance hydrogen atoms

There are 4 hydrogen atoms in $CH_3OH$. So, the coefficient of $H_2O$ should be 2 to balance hydrogen. $CH_3OH + O_2\rightarrow CO_2+2H_2O$

Step3: Balance oxygen atoms

On the right - hand side, there are 4 oxygen atoms in $CO_2$ and $2H_2O$ combined. On the left - hand side, there is 1 oxygen atom in $CH_3OH$. So, the coefficient of $O_2$ should be $\frac{3}{2}$ to balance oxygen. But we usually want whole - number coefficients, so we multiply the entire equation by 2. $2CH_3OH + 3O_2\rightarrow2CO_2 + 4H_2O$

Answer:

2, 3, 2, 4