what is the balanced equation for this reaction? hclo₄ + mg(oh)₂ → 2hclo₄ + mg(oh)₂ → mg(clo₄)₂ + 2h₂o hclo₄…

Explanation:

Step1: Analyze Reactants and Products

The reaction is between a strong acid ($\ce{HClO4}$) and a base ($\ce{Mg(OH)2}$), a neutralization reaction producing a salt ($\ce{Mg(ClO4)2}$) and water ($\ce{H2O}$).

Step2: Balance Magnesium (Mg)

Reactant has 1 Mg (in $\ce{Mg(OH)2}$), product $\ce{Mg(ClO4)2}$ has 1 Mg. So Mg is balanced for now.

Step3: Balance Chlorate ($\ce{ClO4^-}$)

Reactant $\ce{HClO4}$ has 1 $\ce{ClO4^-}$, product $\ce{Mg(ClO4)2}$ has 2 $\ce{ClO4^-}$. So we need 2 $\ce{HClO4}$ to balance $\ce{ClO4^-}$.

Step4: Balance Hydroxide and Water

Reactant $\ce{Mg(OH)2}$ has 2 $\ce{OH^-}$, $\ce{2HClO4}$ has 2 $\ce{H^+}$. $\ce{H^+ + OH^- -> H2O}$, so 2 $\ce{H2O}$ are formed. Now check the equation: $2\ce{HClO4} + \ce{Mg(OH)2} -> \ce{Mg(ClO4)2} + 2\ce{H2O}$.

Answer:

A. $2\ce{HClO4} + \ce{Mg(OH)2} \rightarrow \ce{Mg(ClO4)2} + 2\ce{H2O}$ (assuming the first option is labeled A, with the given equation)