bellwork: mass to mole conversion\ncopy the question and answer the following in your notebook. show your…

bellwork: mass to mole conversion\ncopy the question and answer the following in your notebook. show your work.\n1. how many moles are in 254 g of ca₃(po₄)₂?\n2. find the mole of 138 g mgn₃.\n3. find the mole of 90 g c₄h₈o₂.
Answer
Explanation:
Step1: Calculate molar mass of (Ca_3(PO_4)_2)
Atomic masses: (Ca = 40\space g/mol), (P = 31\space g/mol), (O = 16\space g/mol) (Molar\space mass=3\times40 + 2\times(31 + 4\times16)=310\space g/mol)
Step2: Calculate moles of (Ca_3(PO_4)_2)
(n=\frac{m}{M}=\frac{254\space g}{310\space g/mol}\approx0.82\space mol)
Step3: Calculate molar mass of (MgN_3)
Atomic masses: (Mg = 24\space g/mol), (N = 14\space g/mol) (Molar\space mass = 24+3\times14=66\space g/mol)
Step4: Calculate moles of (MgN_3)
(n=\frac{m}{M}=\frac{138\space g}{66\space g/mol}\approx2.09\space mol)
Step5: Calculate molar mass of (C_4H_8O_2)
Atomic masses: (C = 12\space g/mol), (H = 1\space g/mol), (O = 16\space g/mol) (Molar\space mass=4\times12 + 8\times1+2\times16=88\space g/mol)
Step6: Calculate moles of (C_4H_8O_2)
(n=\frac{m}{M}=\frac{90\space g}{88\space g/mol}\approx1.02\space mol)
Answer:
- Approximately (0.82\space mol)
- Approximately (2.09\space mol)
- Approximately (1.02\space mol)