4) calculate the average atomic mass of the following: show all work!!!\nisotope\tmass (amu)\tpercent…

Explanation:

Step1: Recall the formula for average atomic mass

The formula for average atomic mass ($A_{avg}$) is $A_{avg}=\sum_{i} (m_i\times p_i)$, where $m_i$ is the mass of the isotope and $p_i$ is the percent - abundance (expressed as a decimal) of the isotope.

Step2: Calculate the average atomic mass for boron

For boron: The percent - abundance of Boron - 10, $p_1 = 7.50%=0.0750$, and its mass $m_1 = 10.013$ amu. The percent - abundance of Boron - 11, $p_2=92.50% = 0.9250$, and its mass $m_2 = 11.009$ amu. $A_{avg}=(10.013\times0.0750)+(11.009\times0.9250)$ $=0.750975 + 10.183325$ $=10.9343$ amu

Step3: Calculate the average atomic mass for sulfur

For sulfur: The percent - abundance of Sulfur - 32, $p_1 = 95.00%=0.9500$, and its mass $m_1 = 31.972$ amu. The percent - abundance of Sulfur - 33, $p_2 = 0.760%=0.00760$, and its mass $m_2 = 32.971$ amu. The percent - abundance of Sulfur - 34, $p_3 = 4.220%=0.04220$, and its mass $m_3 = 33.967$ amu. $A_{avg}=(31.972\times0.9500)+(32.971\times0.00760)+(33.967\times0.04220)$ $=30.3734+0.2405796 + 1.4334074$ $=32.047387$ amu $\approx32.047$ amu

Step4: Calculate the average atomic mass for chlorine

For chlorine: The percent - abundance of Chlorine - 35, $p_1 = 75.78%=0.7578$, and its mass $m_1 = 34.969$ amu. The percent - abundance of Chlorine - 37, $p_2 = 24.22%=0.2422$, and its mass $m_2 = 36.966$ amu. $A_{avg}=(34.969\times0.7578)+(36.966\times0.2422)$ $=26.4096082+8.9531652$ $=35.3627734$ amu $\approx35.363$ amu

Answer:

Boron average atomic mass: 10.9343 amu Sulfur average atomic mass: 32.047 amu Chlorine average atomic mass: 35.363 amu