calculate the energy required to heat 0.80 kg of cyclohexane from 15.8 °c to 20.9 °c. assume the specific…

calculate the energy required to heat 0.80 kg of cyclohexane from 15.8 °c to 20.9 °c. assume the specific heat capacity of cyclohexane under these conditions is 1.85 j·g⁻¹·k⁻¹. be sure your answer has the correct number of significant digits.

calculate the energy required to heat 0.80 kg of cyclohexane from 15.8 °c to 20.9 °c. assume the specific heat capacity of cyclohexane under these conditions is 1.85 j·g⁻¹·k⁻¹. be sure your answer has the correct number of significant digits.

Answer

Explanation:

Step1: Convert mass to grams

Since (1\ kg = 1000\ g), for (m = 0.80\ kg), we have (m=0.80\times1000\ g = 800\ g).

Step2: Calculate the temperature change

The formula for temperature change (\Delta T=T_{final}-T_{initial}). Given (T_{initial}=15.8^{\circ}C) and (T_{final}=20.9^{\circ}C), then (\Delta T=(20.9 - 15.8)K=5.1K) (since (\Delta T) in (^{\circ}C) is equal to (\Delta T) in (K)).

Step3: Use the heat - formula (Q = mc\Delta T)

The specific heat capacity (c = 1.85\ J\cdot g^{-1}\cdot K^{-1}), (m = 800\ g), (\Delta T=5.1K). Substitute into the formula: (Q=(800\ g)\times(1.85\ J\cdot g^{-1}\cdot K^{-1})\times(5.1K)). First, calculate (800\times1.85 = 1480), then (1480\times5.1=7548\ J).

Answer:

(7.5\times 10^{3}\ J)