calculate the hydrogen ion concentration, h+, of an acid with a ph of 5.8. ph = - log (h+)\n6.31x10^5\n1.58x1…
calculate the hydrogen ion concentration, h+, of an acid with a ph of 5.8. ph = - log (h+)\n6.31x10^5\n1.58x10^(-6)\n6.31x10^(-6)\n1.58x10^6
Answer
Explanation:
Step1: Rearrange the pH formula
Given $pH = -\log([H^+])$, we can rewrite it as $[H^+]=10^{-pH}$.
Step2: Substitute the pH value
Substitute $pH = 5.8$ into the formula $[H^+]=10^{-pH}$, so $[H^+]=10^{- 5.8}$. Using a calculator, $10^{-5.8}\approx1.58\times10^{-6}$.
Answer:
$1.58\times10^{-6}$