calculate the mass of kcl in grams required to prepare 500.00 ml of a 2.85 m solution. be sure your answer…

Explanation:

Step1: Calculate the number of moles

Use the formula $n = M\times V$, where $M$ is molarity and $V$ is volume in liters. First convert volume to liters: $V = 500.00\ mL=0.50000\ L$, $M = 2.85\ mol/L$. Then $n = 2.85\ mol/L\times0.50000\ L = 1.425\ mol$.

Step2: Calculate the molar mass of KCl

The molar mass of $K$ is approximately $39.10\ g/mol$ and of $Cl$ is approximately $35.45\ g/mol$. So the molar mass of $KCl$, $M_{KCl}=39.10\ g/mol + 35.45\ g/mol=74.55\ g/mol$.

Step3: Calculate the mass of KCl

Use the formula $m = n\times M$. Substitute $n = 1.425\ mol$ and $M = 74.55\ g/mol$ into it. So $m=1.425\ mol\times74.55\ g/mol = 106.23375\ g\approx106.2\ g$ (4 significant - digits).

Answer:

$106.2$