calculate the molality of a solution that was made by dissolving 4.9 g of h2so4 in 50 g of water. use…

Explanation:

Step1: Calculate moles of solute ($H_2SO_4$)

The molar mass of $H_2SO_4$ is $M=(2\times1)+32+(4\times16)=98\ g/mol$. The number of moles of $H_2SO_4$, $n=\frac{m}{M}$, where $m = 4.9\ g$. So $n=\frac{4.9\ g}{98\ g/mol}=0.05\ mol$.

Step2: Convert mass of solvent to kg

The mass of water (solvent) is $m_{solvent}=50\ g = 0.05\ kg$.

Step3: Calculate molality

Molality $m=\frac{n}{m_{solvent}}$. Substituting $n = 0.05\ mol$ and $m_{solvent}=0.05\ kg$, we get $m=\frac{0.05\ mol}{0.05\ kg}=1\ m$.

Answer:

1 m