calculate the molecular formula for a compound with a molar mass of 150.0 g/mol and an empirical formula of…

calculate the molecular formula for a compound with a molar mass of 150.0 g/mol and an empirical formula of ch₂o.\nstep 1: calculate the molar mass for the empirical formula.\nwhat is the molar mass of ch₂o?\n(c = 12.01 amu, h = 1.01 amu, o = 16.00 amu)\n? g/mol ch₂o

calculate the molecular formula for a compound with a molar mass of 150.0 g/mol and an empirical formula of ch₂o.\nstep 1: calculate the molar mass for the empirical formula.\nwhat is the molar mass of ch₂o?\n(c = 12.01 amu, h = 1.01 amu, o = 16.00 amu)\n? g/mol ch₂o

Answer

Explanation:

Step1: Calculate molar - mass of empirical formula

The molar mass of $CH_2O$ is calculated as follows: For carbon ($C$), there is 1 atom with a molar - mass of $12.01\ g/mol$. For hydrogen ($H$), there are 2 atoms with a molar - mass of $1.01\ g/mol$ each, and for oxygen ($O$), there is 1 atom with a molar - mass of $16.00\ g/mol$. $M_{CH_2O}=1\times12.01 + 2\times1.01+1\times16.00$ $M_{CH_2O}=12.01 + 2.02+16.00$ $M_{CH_2O}=30.03\ g/mol$

Step2: Determine the ratio of molar masses

Let $n$ be the ratio of the molar mass of the molecular formula to the molar mass of the empirical formula. $n=\frac{M_{molecular}}{M_{empirical}}=\frac{150.0\ g/mol}{30.03\ g/mol}\approx5$

Step3: Find the molecular formula

Multiply the sub - scripts in the empirical formula $CH_2O$ by $n = 5$. The molecular formula is $C_{5}H_{10}O_{5}$

Answer:

$C_{5}H_{10}O_{5}$