calculate the percent error for the following measurements:\npart 1 of 2\nthe density of alcohol (ethanol)…

calculate the percent error for the following measurements:\npart 1 of 2\nthe density of alcohol (ethanol) is found to be 0.8026 $\frac{g}{ml}$ (true value = 0.7980 $\frac{g}{ml}$). be sure your answer has the correct number of significant digits.\n%\npart 2 of 2\nthe mass of gold in an earring is analyzed to be 0.8406 g (true value = 0.8644 g). be sure your answer has the correct number of significant digits.\n%

calculate the percent error for the following measurements:\npart 1 of 2\nthe density of alcohol (ethanol) is found to be 0.8026 $\frac{g}{ml}$ (true value = 0.7980 $\frac{g}{ml}$). be sure your answer has the correct number of significant digits.\n%\npart 2 of 2\nthe mass of gold in an earring is analyzed to be 0.8406 g (true value = 0.8644 g). be sure your answer has the correct number of significant digits.\n%

Answer

Explanation:

Step1: Recall percent - error formula

Percent error=$\left|\frac{\text{measured value}-\text{true value}}{\text{true value}}\right|\times100%$

Step2: Calculate percent error for alcohol density

Measured value of alcohol density $= 0.8026\frac{g}{mL}$, true value $= 0.7980\frac{g}{mL}$ Percent error$=\left|\frac{0.8026 - 0.7980}{0.7980}\right|\times100%=\left|\frac{0.0046}{0.7980}\right|\times100%\approx0.58%$

Step3: Calculate percent error for gold mass

Measured value of gold mass $= 0.8406g$, true value $= 0.8644g$ Percent error$=\left|\frac{0.8406 - 0.8644}{0.8644}\right|\times100%=\left|\frac{- 0.0238}{0.8644}\right|\times100%\approx2.76%$

Answer:

Part 1 of 2: $0.58%$ Part 2 of 2: $2.76%$