calculate the percent ionization of a weak acid with a concentration of 2.75 m and a ph of…

Explanation:

Step1: Find the hydrogen - ion concentration

The formula for pH is $pH = -\log[H^+]$. Rearranging for $[H^+]$, we get $[H^+]=10^{-pH}$. Given $pH = 1.95$, then $[H^+]=10^{- 1.95}\ M$. $[H^+]=0.0112\ M$.

Step2: Calculate the percent ionization

The formula for percent ionization of a weak acid is $\text{Percent Ionization}=\frac{[H^+]}{[HA]_0}\times100%$, where $[HA]_0$ is the initial concentration of the weak acid. Given $[HA]_0 = 2.75\ M$ and $[H^+]=0.0112\ M$. $\text{Percent Ionization}=\frac{0.0112}{2.75}\times100%$. $\text{Percent Ionization}=0.41%$.

Answer:

C. 0.41%