calculate the volume in milliliters of a 0.260 mol/l barium acetate solution that contains 25.0 g of barium…

calculate the volume in milliliters of a 0.260 mol/l barium acetate solution that contains 25.0 g of barium acetate (ba(c₂h₃o₂)₂). be sure your answer has the correct number of significant digits. ml
Answer
Explanation:
For (Mg(s)+FeCl_2(aq)\to MgCl_2(aq) + Fe(s))
A single - substitution reaction has the general form (A + BC\to AC + B). Here, (Mg) (a more reactive metal) replaces (Fe) in (FeCl_2). So, it is a single - substitution reaction.
For (PbCl_2(aq)+FeSO_4(aq)\to FeCl_2(aq)+PbSO_4(s))
A double - substitution reaction has the general form (AB+CD\to AD + CB). In this reaction, (Pb^{2 +}) and (Fe^{2+}) exchange their anions ((Cl^{-}) and (SO_{4}^{2-})). So, it is a double - substitution reaction.
For (Mg(s)+Cl_2(g)\to MgCl_2(s))
A combination reaction has the general form (A + B\to AB). Here, (Mg) and (Cl_2) combine to form (MgCl_2). So, it is a combination reaction.
For (K_2CO_3(s)\to K_2O(s)+CO_2(g))
A decomposition reaction has the general form (AB\to A + B). Here, (K_2CO_3) decomposes into (K_2O) and (CO_2). So, it is a decomposition reaction.
Answer:
- (Mg(s)+FeCl_2(aq)\to MgCl_2(aq) + Fe(s)): single substitution
- (PbCl_2(aq)+FeSO_4(aq)\to FeCl_2(aq)+PbSO_4(s)): double substitution
- (Mg(s)+Cl_2(g)\to MgCl_2(s)): combination
- (K_2CO_3(s)\to K_2O(s)+CO_2(g)): decomposition