in a calorimeter, 100 g of ice melts at 0°c. the enthalpy of fusion of the ice is 334 j/g. how much heat was…

in a calorimeter, 100 g of ice melts at 0°c. the enthalpy of fusion of the ice is 334 j/g. how much heat was absorbed?\n334 j\n33.4 j\n33.4 kj\n334 kj

in a calorimeter, 100 g of ice melts at 0°c. the enthalpy of fusion of the ice is 334 j/g. how much heat was absorbed?\n334 j\n33.4 j\n33.4 kj\n334 kj

Answer

Explanation:

Step1: Identify the formula

The heat absorbed during a phase - change is given by $Q = m\times\Delta H_f$, where $m$ is the mass and $\Delta H_f$ is the enthalpy of fusion.

Step2: Substitute the given values

We have $m = 100\ g$ and $\Delta H_f=334\ J/g$. So, $Q=100\ g\times334\ J/g$.

Step3: Calculate the heat

$Q = 33400\ J$. Since $1\ kJ = 1000\ J$, then $Q=\frac{33400}{1000}\ kJ=33.4\ kJ$.

Answer:

33.4 kJ