a certain ionic compound (x) has a solubility in water of (0.783\frac{g}{ml}) at (10.^{circ}c). calculate…

a certain ionic compound (x) has a solubility in water of (0.783\frac{g}{ml}) at (10.^{circ}c). calculate the mass of (x) required to prepare (8.0 l) of a saturated solution of (x) in water at this temperature.\nbe sure your answer has the correct unit symbol and 2 significant digits.

a certain ionic compound (x) has a solubility in water of (0.783\frac{g}{ml}) at (10.^{circ}c). calculate the mass of (x) required to prepare (8.0 l) of a saturated solution of (x) in water at this temperature.\nbe sure your answer has the correct unit symbol and 2 significant digits.

Answer

Explanation:

Step1: Convert volume to mL

We know that $1\ L = 1000\ mL$, so for $V = 8.0\ L$, $V=8.0\times1000\ mL = 8000\ mL$.

Step2: Calculate the mass

The solubility is $0.783\ \frac{g}{mL}$. Using the formula $m = S\times V$ (where $S$ is solubility and $V$ is volume), we have $m=0.783\ \frac{g}{mL}\times8000\ mL$. $m = 0.783\times8000\ g=6264\ g$. Rounding to 2 significant - digits, $m\approx6300\ g$.

Answer:

$6300\ g$