ch4 + 2o2 --> co2 + 2h2o\nthe reaction produces how many moles of co2 from 11 moles of o2?\nround to keep 2…

ch4 + 2o2 --> co2 + 2h2o\nthe reaction produces how many moles of co2 from 11 moles of o2?\nround to keep 2 decimal places. ex: ( 5.00moleh2o)\nbalanced eq. ch4 + 2 o2 -> co2 + 2 h2o\n1 mole co2 = 2 mole o2\n2 given 11.00 mole o2\n3 want mole co2\n4 set - up mole co2 = 11 * (1 / 2)\n5? mole co2

ch4 + 2o2 --> co2 + 2h2o\nthe reaction produces how many moles of co2 from 11 moles of o2?\nround to keep 2 decimal places. ex: ( 5.00moleh2o)\nbalanced eq. ch4 + 2 o2 -> co2 + 2 h2o\n1 mole co2 = 2 mole o2\n2 given 11.00 mole o2\n3 want mole co2\n4 set - up mole co2 = 11 * (1 / 2)\n5? mole co2

Answer

Explanation:

Step1: Identify mole - ratio

From the balanced equation $CH_4 + 2O_2\rightarrow CO_2+2H_2O$, the mole - ratio of $O_2$ to $CO_2$ is $2:1$.

Step2: Set up calculation

Let $x$ be the number of moles of $CO_2$. We know that $\frac{\text{moles of }CO_2}{\text{moles of }O_2}=\frac{1}{2}$. Given 11 moles of $O_2$, we have $x = 11\times\frac{1}{2}$.

Step3: Calculate result

$x=\frac{11}{2}=5.50$

Answer:

$5.50$ mole $CO_2$