chapter 9 section 5 #1\nwhat is the molarity of a solution made by dissolving 18.5 g of calcium hydroxide in…

Explanation:

Step1: Calculate molar mass of $Ca(OH)_2$

The molar mass of $Ca$ is $40.08\ g/mol$, $O$ is $16.00\ g/mol$ and $H$ is $1.01\ g/mol$. For $Ca(OH)_2$, $M = 40.08+(2\times(16.00 + 1.01))=74.10\ g/mol$.

Step2: Calculate moles of $Ca(OH)_2$

Use the formula $n=\frac{m}{M}$, where $m = 18.5\ g$ and $M = 74.10\ g/mol$. So $n=\frac{18.5}{74.10}\approx0.25\ mol$.

Step3: Convert volume to liters

The volume $V = 750.0\ mL=0.7500\ L$.

Step4: Calculate molarity

Use the formula $M=\frac{n}{V}$, where $n = 0.25\ mol$ and $V = 0.7500\ L$. So $M=\frac{0.25}{0.7500}\approx0.333\ M$.

Answer:

D. $0.333\ M$