the chemical equation for the combustion of acetylene (c₂h₂) is given below.\n2c₂h₂(g) + 5o₂(g)→4co₂(g) +…

the chemical equation for the combustion of acetylene (c₂h₂) is given below.\n2c₂h₂(g) + 5o₂(g)→4co₂(g) + 2h₂o(g)\nwhat volume of oxygen at stp is required for the complete combustion of 100.50 ml of c₂h₂?\n201 ml\n201.00 ml\n251 ml\n251.25 ml

the chemical equation for the combustion of acetylene (c₂h₂) is given below.\n2c₂h₂(g) + 5o₂(g)→4co₂(g) + 2h₂o(g)\nwhat volume of oxygen at stp is required for the complete combustion of 100.50 ml of c₂h₂?\n201 ml\n201.00 ml\n251 ml\n251.25 ml

Answer

Explanation:

Step1: Determine mole - ratio from equation

From the balanced chemical equation $2C_2H_2(g)+5O_2(g)\longrightarrow4CO_2(g) + 2H_2O(g)$, the mole - ratio of $C_2H_2$ to $O_2$ is $n_{C_2H_2}:n_{O_2}=2:5$.

Step2: Use Avogadro's law at STP

At STP, the volume ratio of gases is equal to their mole ratio. Let $V_{C_2H_2} = 100.50\ mL$ and $V_{O_2}$ be the volume of oxygen. Then $\frac{V_{C_2H_2}}{V_{O_2}}=\frac{n_{C_2H_2}}{n_{O_2}}$. We know $\frac{n_{C_2H_2}}{n_{O_2}}=\frac{2}{5}$, so $V_{O_2}=\frac{5}{2}V_{C_2H_2}$.

Step3: Calculate volume of oxygen

Substitute $V_{C_2H_2}=100.50\ mL$ into the formula: $V_{O_2}=\frac{5}{2}\times100.50\ mL = 251.25\ mL$.

Answer:

251.25 mL