the chemical equation below shows the decomposition of ammonium nitrate (nh4no3). nh4no3 → n2o + 2h2o a…

the chemical equation below shows the decomposition of ammonium nitrate (nh4no3). nh4no3 → n2o + 2h2o a chemist who is performing this reaction starts with 160.1 g of nh4no3. the molar mass of nh4no3 is 80.03 g/mol; the molar mass of water (h2o) is 18.01 g/mol. what mass, in grams, of h2o is produced? 9.01 grams 18.01 grams 36.03 grams 72.06 grams

the chemical equation below shows the decomposition of ammonium nitrate (nh4no3). nh4no3 → n2o + 2h2o a chemist who is performing this reaction starts with 160.1 g of nh4no3. the molar mass of nh4no3 is 80.03 g/mol; the molar mass of water (h2o) is 18.01 g/mol. what mass, in grams, of h2o is produced? 9.01 grams 18.01 grams 36.03 grams 72.06 grams

Answer

Explanation:

Step1: Calculate moles of NH₄NO₃

Use the formula $n=\frac{m}{M}$, where $n$ is the number of moles, $m$ is the mass, and $M$ is the molar - mass. Given $m = 160.1$ g and $M=80.03$ g/mol. $n_{NH_4NO_3}=\frac{160.1}{80.03}=2$ mol

Step2: Determine mole ratio

From the balanced chemical equation $NH_4NO_3\rightarrow N_2O + 2H_2O$, the mole ratio of $NH_4NO_3$ to $H_2O$ is $1:2$. So, if $n_{NH_4NO_3}=2$ mol, then $n_{H_2O}=2\times n_{NH_4NO_3}=4$ mol.

Step3: Calculate mass of H₂O

Use the formula $m = n\times M$. Given $n = 4$ mol and $M = 18.01$ g/mol for $H_2O$. $m_{H_2O}=4\times18.01 = 72.04\approx72.06$ g

Answer:

72.06 grams