the chemical equation below shows the reaction between carbon dioxide (co₂) and lithium hydroxide (lioh)…

the chemical equation below shows the reaction between carbon dioxide (co₂) and lithium hydroxide (lioh). co₂ + 2lioh → li₂co₃ + h₂o. the molar mass co₂ is 44.01 g/mol. how many moles of lioh are needed to react completely with 25.5 g of co₂? 0.290 moles 0.579 moles 1.16 moles 1.73 moles

the chemical equation below shows the reaction between carbon dioxide (co₂) and lithium hydroxide (lioh). co₂ + 2lioh → li₂co₃ + h₂o. the molar mass co₂ is 44.01 g/mol. how many moles of lioh are needed to react completely with 25.5 g of co₂? 0.290 moles 0.579 moles 1.16 moles 1.73 moles

Answer

Explanation:

Step1: Calculate moles of CO₂

Use the formula $n=\frac{m}{M}$, where $n$ is moles, $m$ is mass and $M$ is molar - mass. Given $m = 25.5\ g$ and $M = 44.01\ g/mol$ for $CO_2$. So, $n_{CO_2}=\frac{25.5\ g}{44.01\ g/mol}\approx0.579\ mol$.

Step2: Determine moles of LiOH from mole - ratio

From the balanced chemical equation $CO_2 + 2LiOH\rightarrow Li_2CO_3+H_2O$, the mole - ratio of $CO_2$ to $LiOH$ is $1:2$. So, $n_{LiOH}=2\times n_{CO_2}$. Substituting $n_{CO_2}=0.579\ mol$, we get $n_{LiOH}=2\times0.579\ mol = 1.16\ mol$.

Answer:

C. 1.16 moles