the chemical equation below shows the reaction between carbon dioxide (co₂) and lithium hydroxide…

the chemical equation below shows the reaction between carbon dioxide (co₂) and lithium hydroxide (lioh).\nco₂ + 2lioh → li₂co₃ + h₂o\nthe molar mass co₂ is 44.01 g/mol. how many moles of lioh are needed to react completely with 25.5 g of co₂?\n0.290 moles\n0.579 moles\n1.16 moles\n1.73 moles

the chemical equation below shows the reaction between carbon dioxide (co₂) and lithium hydroxide (lioh).\nco₂ + 2lioh → li₂co₃ + h₂o\nthe molar mass co₂ is 44.01 g/mol. how many moles of lioh are needed to react completely with 25.5 g of co₂?\n0.290 moles\n0.579 moles\n1.16 moles\n1.73 moles

Answer

Explanation:

Step1: Calculate moles of CO₂

Use the formula $n=\frac{m}{M}$, where $n$ is moles, $m$ is mass and $M$ is molar - mass. Given $m = 25.5$ g and $M = 44.01$ g/mol for $CO_2$. So, $n_{CO_2}=\frac{25.5}{44.01}\approx0.579$ mol.

Step2: Use mole - ratio from the balanced equation

The balanced equation is $CO_2 + 2LiOH\rightarrow Li_2CO_3+H_2O$. The mole - ratio of $CO_2$ to $LiOH$ is $1:2$. So, $n_{LiOH}=2\times n_{CO_2}$. Substitute $n_{CO_2}=0.579$ mol into the equation: $n_{LiOH}=2\times0.579 = 1.16$ mol.

Answer:

1.16 moles