this is the chemical formula for iron(ii) hydroxide: fe(oh)₂. calculate the mass percent of oxygen in…

this is the chemical formula for iron(ii) hydroxide: fe(oh)₂. calculate the mass percent of oxygen in iron(ii) hydroxide. round your answer to the nearest percentage.
Answer
Explanation:
Step1: Calculate molar mass of Fe(OH)₂
The molar mass of Fe is approximately 55.85 g/mol, O is approximately 16 g/mol, and H is approximately 1.01 g/mol. For Fe(OH)₂, molar mass $M = 55.85+(16 + 1.01)\times2=55.85 + 34.02=89.87$ g/mol
Step2: Calculate mass of oxygen in Fe(OH)₂
There are 2 oxygen atoms in Fe(OH)₂, so mass of oxygen $m_O=16\times2 = 32$ g/mol
Step3: Calculate mass - percent of oxygen
Mass - percent of oxygen $=\frac{m_O}{M}\times100%=\frac{32}{89.87}\times100%\approx36%$
Answer:
36%