this is the chemical formula for lead(ii) nitrate: $pb(no_3)_2$. calculate the mass percent of nitrogen in…

Explanation:

Step1: Find atomic masses

Atomic mass of Pb = 207.2 g/mol, N = 14.01 g/mol, O = 16.00 g/mol.

Step2: Calculate molar mass of $Pb(NO_3)_2$

$M = 207.2+(14.01 + 16.00\times3)\times2=207.2+(14.01 + 48)\times2=207.2 + 62.01\times2=207.2+124.02 = 331.22$ g/mol.

Step3: Calculate total mass of nitrogen in $Pb(NO_3)_2$

There are 2 N atoms, so mass of N = $14.01\times2 = 28.02$ g/mol.

Step4: Calculate mass - percent of nitrogen

Mass - percent of N=$\frac{28.02}{331.22}\times100%\approx8%$.

Answer:

8%