this is the chemical formula for zinc bromate: $\text{zn(bro}_3\text{)}_2$. calculate the mass percent of…

Explanation:

Step1: Find molar masses

Molar mass of Zn = $65.38\ \text{g/mol}$, Br = $79.90\ \text{g/mol}$, O = $16.00\ \text{g/mol}$

Step2: Calculate total mass of Br

There are 2 Br atoms: $2 \times 79.90 = 159.80\ \text{g/mol}$

Step3: Calculate molar mass of $\text{Zn(BrO}_3\text{)}_2$

$$65.38 + 2\times(79.90 + 3\times16.00) = 65.38 + 2\times(79.90+48.00) = 65.38 + 2\times127.90 = 65.38 + 255.80 = 321.18\ \text{g/mol}$$

Step4: Compute mass percent of Br

$$\text{Mass percent} = \frac{\text{Total mass of Br}}{\text{Molar mass of Zn(BrO}_3\text{)}_2} \times 100% = \frac{159.80}{321.18} \times 100% \approx 49.75%$$

Step5: Round to nearest percentage

Round $49.75%$ to 50%

Answer:

50%