6 a chemist decomposes 60.0 grams of a purple powder into 32.8 grams of the element chlorine (cl) and an…

6 a chemist decomposes 60.0 grams of a purple powder into 32.8 grams of the element chlorine (cl) and an unmeasured amount of the element cobalt (co). the chemist uses the results of this experiment to help him determine the recipe for making this purple powder from its elements. he then decides to make 2.00 kg of it. how much cobalt and how much chlorine gas will he need?

6 a chemist decomposes 60.0 grams of a purple powder into 32.8 grams of the element chlorine (cl) and an unmeasured amount of the element cobalt (co). the chemist uses the results of this experiment to help him determine the recipe for making this purple powder from its elements. he then decides to make 2.00 kg of it. how much cobalt and how much chlorine gas will he need?

Answer

Explanation:

Step1: Find mass of cobalt in 60.0g sample

According to law of conservation of mass, mass of cobalt (m_{Co}=60.0 - 32.8=27.2)g.

Step2: Find mass ratios

Mass ratio of (Cl:Co = 32.8:27.2). Simplify ratio: divide both by 4, (8.2:6.8), then divide by 2, (4.1:3.4). Total parts (=4.1 + 3.4=7.5)

Step3: Convert 2.00kg to grams

(2.00\space kg=2000\space g)

Step4: Calculate mass of chlorine

Mass of (Cl=\frac{4.1}{7.5}\times2000=\frac{8200}{7.5}\approx1093.33\space g)

Step5: Calculate mass of cobalt

Mass of (Co=\frac{3.4}{7.5}\times2000=\frac{6800}{7.5}\approx906.67\space g)

Answer:

He will need approximately (1093.33\space g) of chlorine gas and (906.67\space g) of cobalt.