a chemist prepares a solution of iron(iii) bromide (febr₃) by measuring out 1.3×10² μmol of iron(iii)…

a chemist prepares a solution of iron(iii) bromide (febr₃) by measuring out 1.3×10² μmol of iron(iii) bromide into a 350. ml volumetric flask and filling the flask to the mark with water. calculate the concentration in μmol/l of the chemists iron(iii) bromide solution. be sure your answer has the correct number of significant digits.

a chemist prepares a solution of iron(iii) bromide (febr₃) by measuring out 1.3×10² μmol of iron(iii) bromide into a 350. ml volumetric flask and filling the flask to the mark with water. calculate the concentration in μmol/l of the chemists iron(iii) bromide solution. be sure your answer has the correct number of significant digits.

Answer

Explanation:

Step1: Convert volume to liters

The volume of the solution is $V = 350\ mL$. Since $1\ L=1000\ mL$, then $V = 350\ mL\times\frac{1\ L}{1000\ mL}=0.350\ L$.

Step2: Calculate the concentration

The concentration $C$ is given by the formula $C=\frac{n}{V}$, where $n = 1.3\times10^{2}\ \mu mol$ is the amount of solute and $V$ is the volume of the solution. Substituting the values, we get $C=\frac{1.3\times 10^{2}\ \mu mol}{0.350\ L}\approx371\ \mu mol/L$.

Answer:

$371\ \mu mol/L$