a chemist prepares a solution of sodium hyposulfate (na₂s₂o₃) by measuring out 34.2 μmol of sodium…

a chemist prepares a solution of sodium hyposulfate (na₂s₂o₃) by measuring out 34.2 μmol of sodium hyposulfate into a 50. ml volumetric flask and filling the flask to the mark with water. calculate the concentration in μmol/l of the chemists sodium hyposulfate solution. be sure your answer has the correct number of significant digits.
Answer
Explanation:
Step1: Convert volume to liters
The volume of the flask is $V = 50.\text{ mL}$. Since $1\text{ L}=1000\text{ mL}$, then $V = 50.\text{ mL}\times\frac{1\text{ L}}{1000\text{ mL}}=0.050\text{ L}$.
Step2: Calculate the concentration
The formula for concentration $C$ is $C=\frac{n}{V}$, where $n = 34.2\ \mu\text{mol}$ is the amount of solute and $V$ is the volume of the solution. Substituting the values, we get $C=\frac{34.2\ \mu\text{mol}}{0.050\text{ L}} = 684\ \mu\text{mol/L}$.
Answer:
$684\ \mu\text{mol/L}$