chemistry atomic structure practice i\nx = element symbol\na = mass number # of protons (p) + # neutrons…

chemistry atomic structure practice i\nx = element symbol\na = mass number # of protons (p) + # neutrons (n)\nz = atomic number # of protons\nn = # of neutrons\na - z = n\na typical isotopic symbol takes this form: $_z^a x$\nex. the isotopic symbol for fluorine would be $_{9}^{19}f$\nfill in the missing items in the table below.\nname symbol z a #p #e #n isotopic symbol\nna 23\n17 35\npotassium 39\nfill in the missing items in the table below.\nname symbol z a #p #e #n isotopic symbol\np 31\niron 56\n127 53\nfill in the missing items in the table below.\nname symbol z a #p #e #n isotopic symbol\nsilver 108\n36 84\nw 184

chemistry atomic structure practice i\nx = element symbol\na = mass number # of protons (p) + # neutrons (n)\nz = atomic number # of protons\nn = # of neutrons\na - z = n\na typical isotopic symbol takes this form: $_z^a x$\nex. the isotopic symbol for fluorine would be $_{9}^{19}f$\nfill in the missing items in the table below.\nname symbol z a #p #e #n isotopic symbol\nna 23\n17 35\npotassium 39\nfill in the missing items in the table below.\nname symbol z a #p #e #n isotopic symbol\np 31\niron 56\n127 53\nfill in the missing items in the table below.\nname symbol z a #p #e #n isotopic symbol\nsilver 108\n36 84\nw 184

Answer

Explanation:

Step1: Recall atomic - structure relationships

Atomic number ($Z$) = number of protons ($#p$), for a neutral atom, number of electrons ($#e$) = number of protons ($#p$), number of neutrons ($#n$)=$A - Z$, and isotopic symbol is $^{A}_{Z}X$.

Step2: First table - row 1 (Sodium)

The symbol is $Na$. Atomic number of sodium ($Z$) is 11. Since $A = 23$, $#p=Z = 11$, $#e=#p = 11$, $#n=A - Z=23 - 11 = 12$, and isotopic symbol is $^{23}_{11}Na$.

Step3: First table - row 2 (Chlorine)

$Z = 17$, $A = 35$. So $#p = 17$, $#e=#p = 17$, $#n=A - Z=35 - 17 = 18$, symbol is $Cl$, and isotopic symbol is $^{35}_{17}Cl$.

Step4: First table - row 3 (Potassium)

Symbol of potassium is $K$. Atomic number of potassium ($Z$) is 19. Since $A = 39$, $#p=Z = 19$, $#e=#p = 19$, $#n=A - Z=39 - 19 = 20$, and isotopic symbol is $^{39}_{19}K$.

Step5: Second table - row 1 (Phosphorus)

Symbol is $P$. Atomic number of phosphorus ($Z$) is 15. Since $A = 31$, $#p=Z = 15$, $#e=#p = 15$, $#n=A - Z=31 - 15 = 16$, and isotopic symbol is $^{31}_{15}P$.

Step6: Second table - row 2 (Iron)

Symbol of iron is $Fe$. Atomic number of iron ($Z$) is 26. Since $A = 56$, $#p=Z = 26$, $#e=#p = 26$, $#n=A - Z=56 - 26 = 30$, and isotopic symbol is $^{56}_{26}Fe$.

Step7: Second table - row 3 (Iodine)

$Z = 53$, $A = 127$. So $#p = 53$, $#e=#p = 53$, $#n=A - Z=127 - 53 = 74$, symbol is $I$, and isotopic symbol is $^{127}_{53}I$.

Step8: Third table - row 1 (Silver)

Symbol of silver is $Ag$. Atomic number of silver ($Z$) is 47. Since $A = 108$, $#p=Z = 47$, $#e=#p = 47$, $#n=A - Z=108 - 47 = 61$, and isotopic symbol is $^{108}_{47}Ag$.

Step9: Third table - row 2 (Krypton)

$Z = 36$, $A = 84$. So $#p = 36$, $#e=#p = 36$, $#n=A - Z=84 - 36 = 48$, symbol is $Kr$, and isotopic symbol is $^{84}_{36}Kr$.

Step10: Third table - row 3 (Tungsten)

Symbol is $W$. Atomic number of tungsten ($Z$) is 74. Since $A = 184$, $#p=Z = 74$, $#e=#p = 74$, $#n=A - Z=184 - 74 = 110$, and isotopic symbol is $^{184}_{74}W$.

Answer:

Name Symbol Z A #p #e #n Isotopic Symbol
Sodium Na 11 23 11 11 12 $^{23}_{11}Na$
Chlorine Cl 17 35 17 17 18 $^{35}_{17}Cl$
Potassium K 19 39 19 19 20 $^{39}_{19}K$
Phosphorus P 15 31 15 15 16 $^{31}_{15}P$
Iron Fe 26 56 26 26 30 $^{56}_{26}Fe$
Iodine I 53 127 53 53 74 $^{127}_{53}I$
Silver Ag 47 108 47 47 61 $^{108}_{47}Ag$
Krypton Kr 36 84 36 36 48 $^{84}_{36}Kr$
Tungsten W 74 184 74 74 110 $^{184}_{74}W$