8. chlorine gas fills a container at stp. the container is placed in a freezer, where the temperature is…
8. chlorine gas fills a container at stp. the container is placed in a freezer, where the temperature is halved. what will happen to the pressure? show work to support your answer.
Answer
Explanation:
Step1: Identify the gas - law
We use Gay - Lussac's law ($\frac{P_1}{T_1}=\frac{P_2}{T_2}$) for a gas at constant volume. At STP, $T_1 = 273\ K$ and let the initial pressure be $P_1$. The new temperature $T_2=\frac{T_1}{2}$.
Step2: Rearrange the formula to solve for $P_2$
From $\frac{P_1}{T_1}=\frac{P_2}{T_2}$, we can cross - multiply to get $P_2=\frac{P_1T_2}{T_1}$. Substitute $T_2 = \frac{T_1}{2}$ into the formula: $P_2=\frac{P_1\times\frac{T_1}{2}}{T_1}$. The $T_1$ terms cancel out, and we find that $P_2=\frac{P_1}{2}$.
Answer:
The pressure will be halved.