8) ___ c₄h₈ + ___ o₂ → ___ co₂ + ___ h₂o\nc = 4 o = 2 | c = 1 h = 2\nh = 8 | o = 3

Explanation:

Step1: Balance carbon atoms

There are 4 carbon atoms in $C_{4}H_{8}$. So, the coefficient of $CO_{2}$ should be 4 to balance the carbon - atoms. The equation becomes $C_{4}H_{8}+ \underline{}\ O_{2}\to4CO_{2}+\underline{}\ H_{2}O$.

Step2: Balance hydrogen atoms

There are 8 hydrogen atoms in $C_{4}H_{8}$. So, the coefficient of $H_{2}O$ should be 4 to balance the hydrogen - atoms. The equation is now $C_{4}H_{8}+\underline{}\ O_{2}\to4CO_{2} + 4H_{2}O$.

Step3: Balance oxygen atoms

On the right - hand side, the total number of oxygen atoms in $4CO_{2}$ and $4H_{2}O$ is $4\times2 + 4\times1=12$. So, the coefficient of $O_{2}$ should be 6 to balance the oxygen atoms.

Answer:

$1\ C_{4}H_{8}+6\ O_{2}\to4\ CO_{2}+4\ H_{2}O$