8. h₂co₃ + lioh → li₂co₃ + h₂o
8. h₂co₃ + lioh → li₂co₃ + h₂o
Answer
Explanation:
Step1: Balance lithium atoms
On the right - hand side, there are 2 lithium atoms in $Li_2CO_3$. So, we need 2 moles of $LiOH$ on the left - hand side. The equation becomes $H_2CO_3+2LiOH\rightarrow Li_2CO_3 + H_2O$.
Step2: Balance hydrogen and oxygen atoms
On the left - hand side, we have $2 + 2=4$ hydrogen atoms from $H_2CO_3$ and $2LiOH$, and on the right - hand side, in $Li_2CO_3$ there are 0 hydrogen atoms. In $H_2O$, we need 2 moles to balance the hydrogen atoms. Also, for oxygen atoms, on the left we have $3 + 2 = 5$ oxygen atoms in $H_2CO_3$ and $2LiOH$, and on the right in $Li_2CO_3$ we have 3 oxygen atoms and in $2H_2O$ we have 2 oxygen atoms, which balances the oxygen atoms as well.
Answer:
1, 2, 1, 2