which coefficient is needed in front of nano3 to balance the equation na2s + zn(no3)2 → zns + _nano3?\no…
which coefficient is needed in front of nano3 to balance the equation na2s + zn(no3)2 → zns + _nano3?\no 1\no 2\no 5\no 7
Answer
Explanation:
Step1: Count atoms of each element on reactant side
- For (Na): There are (2) (Na) atoms in (Na_2S).
- For (S): There is (1) (S) atom in (Na_2S) and (1) (S) atom in (ZnS) (already balanced).
- For (Zn): There is (1) (Zn) atom in (Zn(NO_3)_2) and (1) (Zn) atom in (ZnS) (already balanced).
- For (NO_3^-): There are (2) (NO_3^-) groups in (Zn(NO_3)_2).
Step2: Balance (Na) and (NO_3^-) on product side
- Since there are (2) (Na) atoms (from (Na_2S)) and (2) (NO_3^-) groups (from (Zn(NO_3)_2)), we need (2) (NaNO_3) molecules. Because in (NaNO_3), each molecule has (1) (Na) atom and (1) (NO_3^-) group. So, (2\times1 = 2) for (Na) (matches (Na_2S)) and (2\times1=2) for (NO_3^-) (matches (Zn(NO_3)_2)).
The balanced equation is (Na_2S+Zn(NO_3)_2\rightarrow ZnS + 2NaNO_3)
Answer:
2