the colligative effects of 1 molal sugar solution would be ? 1 molal sodium chloride solution.\n\n1. greater…

Explanation:

Step1: Identify the nature of the solutes

Sugar (sucrose) is a non-electrolyte that does not dissociate in water, meaning its van't Hoff factor is $i = 1$.

Step2: Identify the dissociation of sodium chloride

Sodium chloride ($NaCl$) is a strong electrolyte that dissociates into two ions ($Na^{+}$ and $Cl^{-}$), resulting in a van't Hoff factor of $i = 2$.

Step3: Compare the effective particle concentrations

Colligative properties depend on the total concentration of solute particles. For 1 molal solutions: Effective concentration of sugar = $1 \times 1 = 1\text{ molal}$ Effective concentration of $NaCl$ = $1 \times 2 = 2\text{ molal}$

Step4: Determine the relative magnitude

Since the effective particle concentration of the sugar solution is lower than that of the $NaCl$ solution, its colligative effects are smaller.

Answer:

2. less than