2) complete the following, writing your answer in standard scientific notation.\na) 0.00918 = 9.18×10⁻³\nb)…

2) complete the following, writing your answer in standard scientific notation.\na) 0.00918 = 9.18×10⁻³\nb) 754,000 = 7.54×10⁵\nc) 101.325×10² = 1.01325×10⁴\nd) (2×10²)(4×10¹²) = 8×10¹⁴\ne) 9×10⁸ / 3×10³ = 3×10⁵\ntoms, elements, compounds & molecules\nthe particle diagram labeled figure 1 represents a(n) ____________ (element or compound). i know this beca\nthe particle diagram labeled figure 2 represents a(n) ____________ (element or compound). i know this beca\neach particle in figure 1 is a(n) ____________ (atom or molecule).\neach particle in figure 2 is a(n) ____________ (atom or molecule).\n4) the density of an unknown metal was found experimentally using water displacement and the data collected is given below.\nvolume of water in the graduated cylinder 55.0 ml\nvolume of water in the graduated cylinder with metal 61.5 ml\nmass of metal 30.36 g\na) calculate the volume of the metal. show your work.\nb) calculate the density of the metal. round your answer to 2 places after the decimal point. show your work.\nc) if the metal was titanium, calculate the percent error (hint: use your periodic table). show your work.\n% error = |expected - experimental|×100 / expected

2) complete the following, writing your answer in standard scientific notation.\na) 0.00918 = 9.18×10⁻³\nb) 754,000 = 7.54×10⁵\nc) 101.325×10² = 1.01325×10⁴\nd) (2×10²)(4×10¹²) = 8×10¹⁴\ne) 9×10⁸ / 3×10³ = 3×10⁵\ntoms, elements, compounds & molecules\nthe particle diagram labeled figure 1 represents a(n) ____________ (element or compound). i know this beca\nthe particle diagram labeled figure 2 represents a(n) ____________ (element or compound). i know this beca\neach particle in figure 1 is a(n) ____________ (atom or molecule).\neach particle in figure 2 is a(n) ____________ (atom or molecule).\n4) the density of an unknown metal was found experimentally using water displacement and the data collected is given below.\nvolume of water in the graduated cylinder 55.0 ml\nvolume of water in the graduated cylinder with metal 61.5 ml\nmass of metal 30.36 g\na) calculate the volume of the metal. show your work.\nb) calculate the density of the metal. round your answer to 2 places after the decimal point. show your work.\nc) if the metal was titanium, calculate the percent error (hint: use your periodic table). show your work.\n% error = |expected - experimental|×100 / expected

Answer

Explanation:

Step1: Calculate volume of metal

Volume of metal = Volume of water with metal - Volume of water $V = 61.5 - 55.0=6.5$ ml

Step2: Calculate density of metal

Density formula is $\rho=\frac{m}{V}$, where $m = 30.36$ g and $V = 6.5$ ml $\rho=\frac{30.36}{6.5}\approx4.67$ g/ml

Step3: Find expected density of titanium

From periodic - table, density of titanium $\rho_{expected}=4.50$ g/ml

Step4: Calculate percent error

Percent error formula is $%error=\frac{\vert\rho_{expected}-\rho_{experimental}\vert}{\rho_{expected}}\times100$ $%error=\frac{\vert4.50 - 4.67\vert}{4.50}\times100=\frac{0.17}{4.50}\times100\approx3.78%$

Answer:

a) Volume of metal: 6.5 ml b) Density of metal: 4.67 g/ml c) Percent error: 3.78%