consider the chemical equation for the combustion of sugar.\n_$c_{6}h_{12}o_{6}(s)$ + _$o_{2}(g)$…
consider the chemical equation for the combustion of sugar.\n_$c_{6}h_{12}o_{6}(s)$ + _$o_{2}(g)$ $\rightarrow$ _$co_{2}(g)$ + _$h_{2}o(l)$\nwhich sequence of coefficients should be placed in the blanks to balance this equation?\no 1,6,6,6\no 6,1,6,1\no 3,3,3,6\no 1,3,3,6
Answer
Answer:
A. 1, 6, 6, 6
Explanation:
Step1: Balance carbon atoms
On the left - hand side, there are 6 carbon atoms in $C_6H_{12}O_6$. In $CO_2$ on the right - hand side, to have 6 carbon atoms, the coefficient of $CO_2$ should be 6.
Step2: Balance hydrogen atoms
There are 12 hydrogen atoms in $C_6H_{12}O_6$. In $H_2O$, since each $H_2O$ molecule has 2 hydrogen atoms, to have 12 hydrogen atoms, the coefficient of $H_2O$ should be 6.
Step3: Balance oxygen atoms
On the right - hand side, in 6 $CO_2$ there are 12 oxygen atoms and in 6 $H_2O$ there are 6 oxygen atoms, so a total of 18 oxygen atoms. In $C_6H_{12}O_6$ there are 6 oxygen atoms. So the number of oxygen atoms from $O_2$ needed is 12, and the coefficient of $O_2$ is 6. So the balanced equation is $C_6H_{12}O_6(s)+6O_2(g)\rightarrow6CO_2(g) + 6H_2O(l)$.