consider the equation below.\ncaco₃(s)⇌cao(s) + co₂(g)\nwhat is the equilibrium constant expression for the…

consider the equation below.\ncaco₃(s)⇌cao(s) + co₂(g)\nwhat is the equilibrium constant expression for the given reaction?\n○ kₑq = \\frac{cao}{caco₃}\n○ kₑq = \\frac{co₂cao}{caco₃}\n○ kₑq = co₂\n○ kₑq = \\frac{1}{co₂}

consider the equation below.\ncaco₃(s)⇌cao(s) + co₂(g)\nwhat is the equilibrium constant expression for the given reaction?\n○ kₑq = \\frac{cao}{caco₃}\n○ kₑq = \\frac{co₂cao}{caco₃}\n○ kₑq = co₂\n○ kₑq = \\frac{1}{co₂}

Answer

Explanation:

Step1: Recall equilibrium constant rules

The equilibrium constant ($K_{eq}$) for a reaction is the ratio of the concentrations of products to reactants, each raised to their stoichiometric coefficients. For pure solids and pure liquids, their concentrations are considered constant and are not included in the $K_{eq}$ expression.

Step2: Analyze reactants and products

In the reaction $\mathrm{CaCO_3(s)\rightleftharpoons CaO(s)+CO_2(g)}$, $\mathrm{CaCO_3}$ and $\mathrm{CaO}$ are solids and $\mathrm{CO_2}$ is a gas.

Step3: Write the equilibrium - constant expression

Since the concentrations of $\mathrm{CaCO_3}$ and $\mathrm{CaO}$ (solids) are not included, the equilibrium - constant expression is $K_{eq} = [\mathrm{CO_2}]$.

Answer:

$K_{eq}=[\mathrm{CO_2}]$ (the third option)