consider the following intermediate chemical equations.\nch4(g)+2o2(g)→co2(g)+2h2o(g)\n2h2o(g)→2h2o(l)\nwhich…

Explanation:

Step1: Identify reactants and products in given equations

First equation: Reactants are $CH_4(g)$ and $2O_2(g)$, products are $CO_2(g)$ and $2H_2O(g)$. Second equation: Reactants are $2H_2O(g)$, product is $2H_2(g)$ and $O_2(g)$.

Step2: Combine equations

When we combine them, we cancel out the common species $2H_2O(g)$. The overall reaction is $CH_4(g)+2O_2(g)\rightarrow CO_2(g) + 2H_2(g)+O_2(g)$, which simplifies to $CH_4(g)+O_2(g)\rightarrow CO_2(g)+2H_2(g)$.

Answer:

$CH_4(g)+O_2(g)\rightarrow CO_2(g)+2H_2(g)$ (assuming the correct combination based on cancelling out common - species between the two given equations)